Fluid Catalytic Cracking Process Engineering Essay
INTRODUCTION
Fluid catalytic cracking process, which is now more than 60 years old, is the cornerstone of most of the petroleum refineries. It has proven to be the most-efficient process available for the conversion of gas oils and residue into more valuable lighter hydrocarbons. Many refiners consider the catalytic cracking process to be the highest profit generating unit in the entire refinery. In earlier times, Fluid Catalytic Cracking Unit (FCCU) was operated broadly in two modes, they are;
Maximum gasoline mode
Maximum distillate mode
But with the advent of Reformulated gasoline (RFG), these are now operated in maximum olefin mode. FCCU is a very sophisticated unit with many factors affecting each other and the overall process. In some processes investigation of factors impact is done by changing one factor at a time while keeping other factors constant. In case of FCCU it is almost practically impossible to obtain a clear indication; as, change in one single factor leads to change(s) in one or more other factors. This whole phenomenon is a natural consequence of the “heat balance” of FCCU. If the unit is to operate at steady state, then the unit has to be in heat balance condition. At this stage the heat requirement in the reactor is satisfied by burning coke in the regenerator and transferring the energy to the reactor through circulating hot catalyst. Heat balance around the reactor-regenerator can be used to predict the effects of process changes although the exact degree of the changes may be difficult to establish. It is one step at a time thought process and rather difficult to pin down exact numbers without a careful study of yields and coke laydown rates as affected by changing variables. In this work a plant data is taken as reference and based on that, calculations have been done to find out the net heat of endothermic reactions occurring in the riser reactor, assuming that the unit is operating at steady state and that the riser is an isothermal one. Then as per the products slate, a 7-lumped model is considered from various literatures and based on the kinetics of reactions, rate equations are formed and with the knowledge of available kinetic parameters the differential temperature drops along the height of the riser are calculated.
PROCESS DESCRIPTION
More than a dozen types of FCCU are operating worldwide. But the basic designs of all these type remain the same. FCCU comprises of two parts;
Riser reactor, in which catalytic cracking reactions occur
Regenerator, in which burning of coke (deposited during cracking) from the catalytic sites is done
Figure 1 shows a schematic diagram of a typical FCCU. The feed is preheated in a furnace and
(Figure: 1- Schematic Diagram of a typical FCCU)
injected at the bottom of the riser along with a small amount of steam. This steam helps in dispersion of feed, good atomization and reduces coke formation by decreasing the partial pressure of hydrocarbon vapours. The feed is subsequently vaporized when it comes in contact with the hot catalyst from regenerator. The hydrocarbon vapours so formed undergo endothermic cracking reactions on their way up through the riser. The expansion of product vapours occurs through the length of the riser and the gas velocity increases with decreasing gas density. Hot catalyst particles provide the sensible heat and latent heat requirements for vaporizing the liquid feed and also endothermic heat of reaction for the cracking reactions. After a certain distance from the entry zone of the riser, the liquid feed is completely vaporized. Cracking reactions continue with the vapours moving up in the riser and the temperature is dropped along the length of the riser due to endothermic nature of cracking. The catalytic cracking is started and also completed in a very short period of time inside the riser reactor in which the catalyst is pushed upward by incorporating steam at various locations along the length of the riser and hydrocarbon vapours. Mixture of catalyst and hydrocarbon vapour travels up in the riser into the reactors. Steams injected at different locations in the riser are as follows,
Fluffing steam at the bottom of the riser
Dispersion steam along with fresh feed injectors
Riser dilution steam above the fresh feed injectors
Dispersion steam along with recycle stream injectors
Aeration steam into the riser “J” bend to fluidize the catalyst
Along with this some other locations are there where steam is injected. They are as follows;
Spent catalyst standpipe aeration steam
Regenerated catalyst standpipe aeration steam
Reactor quench steam
Reactor dome steam
Post riser quench steam
Stripping steam into strippers
Mixture of catalyst and hydrocarbon vapour is discharged from the riser to the riser cyclone assembly. The bulk of the spent catalyst is separated from product vapours in the cyclone assembly. If necessary the vapours leaving the riser cyclones are routed into secondary cyclone assembly located inside the reactor vessel. Separated catalysts flow through each cyclone dip leg into the stripper. Product vapours leave the reactor cyclones and flow into the main fractionator through the reactor overhead vapour line. Quench steam is injected inside the reactor vessel to reduce the temperature, so as to minimize post riser thermal cracking reactions and coke formation. Reactor dome steam is provided to sweep hydrocarbons and avoid dead areas on top of the reactor vessel that may lead to thermal cracking and coking in that area. The separated catalyst from the riser and reactor cyclone assemblies enters the catalyst stripper.
As the catalyst flows down the stripper, it gets stripped off the entrained hydrocarbon vapours by the up flowing steam. Stripping enhances the product recovery and reduces the carryover of hydrocarbon to the regenerator along with the spent catalyst thereof. Fluffing steam ensures the fluidization of the circulating catalyst. Stripped catalyst from the stripper flows into the regenerator dense bed through the spent catalyst standpipe (SCSP). Catalyst level in the stripper is maintained by spent catalyst slide valve (SCSV). Aeration steam is provided in the SCSP to ensure proper flow and fluidization of spent catalyst.
Coke adsorbed on the spent catalyst during cracking reaction is been removed in the regenerator by burning off the coke with air. Air is supplied from the air blower to the regenerator through multiple distributors. Air is also introduced at different locations of the regenerator, they are as follows;
T-grid air
Regenerated catalyst standpipe (RCSP) hopper aeration air
RCSP aeration air
Regenerator fluffing air at the bottom near the “J” bend
The regenerator can be operated in two modes;
Partial combustion mode
Complete combustion mode
For partial combustion mode, a CO boiler is needed to convert CO to CO2. The current discussion is for complete combustion mode regenerator.
Flue gas from the regenerated dense bed flows to the two stage regenerator cyclone assembly. Here the entrained catalyst is separated from the flue gas. The separated catalyst flows back to the dense bed through cyclone dip legs. Flue gas from the cyclone flows out from top of the regenerator through a flue gas line. Total air flow to the regenerator is regulated based on the desired level of oxygen in flue gas. Too low O2 concentration will cause coke build up on regenerated catalyst and CO release from regenerator. Too high O2 concentration will lead to regenerator cooling. So, regenerator flue gas is regularly examined for O2, CO, CO2, NO2, SO2 analysis.
FEED CHARACTERIZATION
The only constant in FCC operation is the frequent change in feedstock quality. That’s why two feeds with similar boiling point ranges can exhibit huge differences in cracking performance and product yields. Feed characterization is one of the most important activities in monitoring the FCC process. Feed characterization is the process of determining physical and chemical properties of the feed. Understanding feed properties and also knowing their impact on unit’s performance is an essential thing. Trouble shooting, catalyst selection, unit optimization and subsequent process evaluation, all depend on feedstock. Feed characterization relates product yields and qualities to feed quality. Analytical techniques like mass spectrometry are sophisticated and not practical for determining complete composition of FCC feedstock. Simpler empirical correlations are often used. They are as follows;
oAPI gravity and UOP K
Boiling range
Average boiling point
Carbon residue
Metals
Sulphur, Nitrogen and Oxygen
oAPI gravity and UOP K
It is a specific gravity relating the density of oil to the density of water. The empirical formula for this is;
oAPI – 131.5 (3.1)
Feed to an FCC can range from 15o to 45o API. If the API gravity increases the charge stock will crack more readily and for the same reaction temperature there will be greater conversion. Secondly at a constant conversion level, there will be greater gasoline yield with slightly lower octane.
A rough indication of the quantities of paraffin present is a characterization factor which relates boiling point to specific gravity, is called the UOP K factor. This is given by;
(3.2)
Where:
CABP = cubic average boiling point, oR
SG = specific gravity at 60 oF
Higher the UOP K value more is the paraffinic nature of the feedstock.
Boiling Range
The boiling range of FCC feed varies from an initial point of 500oF to an endpoint of about 1000oF. There are two boiling point ranges which are used to describe the lighter material in the feed. They are;
Per cent over 430oF
Per cent over 650oF
The first quantifies the amount of gasoline in the feed. The second one quantifies the light fuel oil in the charge.
Average boiling point
Average boiling point of the FCC feed depends on the average molecular weight. An increase in average boiling point and molecular weight will typically cause the following;
The charge will crack more readily, so at constant reactor temperature conversion will increase
At constant conversion, yield of C4 and lighter will decrease
Olefinic content of the product will decrease
Regenerator temperature will tend to rise
At constant conversion, the gasoline yield will increase about 1% for an increase in the molecular weight of 20.
Carbon residue
The carbon residue of a feedstock is an indirect measure of its coke producing nature. Values may be determined by either Conradson or Ramsbottom methods. The carbon residue can be a useful number for determining possible contamination in storage. Entrainment in vacuum tower is a common cause of increased carbon residue. Colour may be used to approximately evaluate the carbon content of the feedstock. Darker stocks tend to have higher carbon residues.
Metals
Organometallic compounds in the FCC feed can cause serious overcracking if the metals deposit on the catalyst. The cleanliness of a chargestock is given by a metals factor:
Fm = Fe + V + 10 (Ni + Cu) (3.3)
Where:
Fm = Metals Factor
Fe = Iron concentration
V = Vanadium concentration
Ni = Nickel concentration
Cu = Copper concentration
All metal concentrations are ppm by weight in the feed. A factor of 1.0 is considered safe, over 3.0 indicate a danger of poisoning of catalyst.
Sulfur, Nitrogen, Oxygen
Sulfur is as undesirable in FCC feed as it is in the feed to most of the refining units, causing corrosion of the equipment and increased difficulty in treating products. At 50% conversion about 35% sulfur charged is converted to H2S, and at 70% conversion the figure will rise to 50%. Nitrogen produces NH3 and CN- in the reactors, and NOx and trace quantities of NH3 in the regenerator. These NH3 and CN- cause plugging and corrosion, while the NOx and NH3 in the flue gas cause environmental problems. Gas oil will absorb oxygen in storage unless the tanks are gas blanketed. This oxygen will combine with the compounds in the oil at about 450oF to form gum, which fouls heat exchangers.
FCC REACTION CHEMISTRY
Cracking reactions are predominantly catalytic, but some non-selective thermal cracking reactions do take place. The two processes proceed via different chemistry. The occurrence of both the reactions is confirmed by distribution of products. Catalytic cracking proceeds mainly via carbenium ion intermediates. There are three dominant reactions in cracking are catalytic cracking, isomerization, hydrogen transfer. The idealized reaction classes are tabled below with specific reactions to support them.
(Table: 1 – idealized reactions of importance in FCCU)
Reaction classes
Specific reactions
Cracking
n-C10H22 n-C7H16 + C3H6 ; 1-C8H16 2C4H8
Hydrogen transfer
4C6H12 3C6H14 + C6H6 ; cyclo-C6H12 + 3 1-C5H10 3n-C5H12 + C6H6
Isomerization
1-C4H8 trans-2-C4H8 ; n-C6H10 iso-C4H10 ; o-C6H4(CH3)2 m- C6H4(CH3)2
Transalkylation
C6H6 + m- C6H4(CH3)2 2C6H5CH3
Cyclization
1-C7H14 CH3-cyclo-C6H11
Dealkylation
Iso-C3H7-C6H5 C6H6 + C3H6
Dehydrogenation
n-C6H14 1-C6H12 + H2
Polymerization
3C2H4 1-C6H12
Paraffin alkylation
1-C4H8 + iso-C4H10 iso-C8H18
Some of the reactions are endothermic in nature and some are exothermic in nature. Each reaction has a heat of reaction associated with it. The overall heat of reaction is the combination of both the types of heat of reactions. Though there are a number of exothermic reactions, then also the net reaction is endothermic. It is apparent that the type and magnitude of reactions have an impact on the heat balance of the unit. If the catalyst is with less hydrogen transfer characteristics, it will cause the net heat of reaction to be more endothermic. This in turn results in higher catalyst circulation and possibly a higher coke yield to maintain the heat balance.
FCC UNIT MATERIAL BALANCE
For this, a complete set of commercial plant data is used. The data is given in subsequent tables below;
FEEDSTOCK
(Table: 2 – Properties of feed components)
Feed
Unit
Hydrotreated
VGO
Un-hydrotreated
VGO
Light Coker Naphtha
Quantity,TMTPA
3200
800
170
% of total feed
wt%
76.74
19.18
4.08
Density @ 15oC
gm/cc
0.894
0.932
0.6762
CCR
wt%
0.1
1.2
–
Sulfur
wt%
0.1
3.32
0.434
Hydrogen content
wt%
13
–
–
Ni + V
wppm
1
6.38
–
Nitrogen
wppm
500
1594
30
ASTM Distillation, vol.%
D-1160, oC
D-1160, oC
D-86, oC
IBP
366
349
36
5
374
379
–
10
385
394
43
30
420
435
49
50
443
468
57
70
485
508
65
90
545
556
75
95
576
573
–
FBP
620
609
86
Bromine no.
107.86
Paraffins
vol.%
46.7
Olefins
vol.%
43.38
Naphthenes
vol.%
7.25
Aromatics
vol.%
2.68
RON, clear
79.4
Diene value
5.31
WATSON K
12.436
MW
82.001
PRODUCT YIELDS
(Table: 3- product yields, Ex-reactor and Perfect fractionator basis)
Products
wt %
Weight (lbs. /hr.)
H2S
0.39
4309
Hydrogen
0.041
606
Methane
1.06
11710
Ethane
1.54
17010
ethylene
1.76
19442
Dry gas
4.401
48768
Propane
2.86
31592
Propylene
9.66
106708
n-butane
1.69
18668
i-butane
5.52
60976
butenes
7.47
82516
LPG
27.2
300460
LCN
14.50
160174
MCN
23.40
257978
HCN
3.90
43082
LCO
16.45
181713
CLO
4.75
153347
COKE
5.01
——-
OPERATING CONDITIONS
(Table: 4- Operating conditions for the Unit)
Riser-Reactor
Unit
Value
Fresh heavy feed rate (VGO)
m3/hr.
533.4
Fresh light feed rate (Coker naphtha)
m3/hr.
30.2
CLO recycle
m3/hr.
46
Riser top temperature
oC
540
Riser top pressure
Kg/cm2
1.5
Feed preheat temperature
oC
350
Regenerator
Air to regenerator (dry basis)
Nm3/hr.
310717
Regenerator pressure
Kg/cm2
1.9
Dense bed temperature
oC
640
Dilute bed temperature
oC
654
Flue gas temperature
oC
657
Blower discharge temperature
oC
226
Stripper
Stripping steam rate
Kg/hr.
5000
Stripping steam temperature
oC
290
Stripping steam pressure
Kg/cm2
10.5
Base temperature
oC
Ambient temperature
oC
35
Flue gas composition
MW= 30.6
O2
vol. %
2.49
CO
vol. %
0.005
CO2
vol. %
15.58
N2
vol. %
81.83
SO2
vol. %
0.085
SO3
vol. %
0.01
Now using the above data, amount of oxygen that was consumed by burning the hydrogen in coke is estimated. All the gas calculations are based upon 100 moles of flue gas. The oxygen consumed for H2O is given by the expression;
O2 consumed = * (vol. % of N2 in flue gas) – 2 * (vol. % of O2 in flue gas)
– 2 * (vol. % of CO2 in flue gas) – (vol. % of CO in flue gas) (5.1)
So, O2 consumed = * (81.83) – 2 * (2.49) – 2 * (15.58) – (0.005)
= 7.36
The weight of the hydrogen and carbon in the coke are calculated;
Weight = 2.016 * (7.36) + 12.01 * (15.58+0.005)
= 202.01
The temperature differentials are calculated; (oF basis)
ÃŽâ€TRR = (Regenerator dense bed temperature – Riser outlet temperature) (5.2)
= 1184 – 1004
ÃŽâ€TRR = 180
ÃŽâ€TRB = (Regenerator fluegas temperature – Blower discharge temperature) (5.3)
= 1215 – 439
ÃŽâ€TRB = 776
ÃŽâ€TRS = (Riser outlet temperature – Stripping steam temperature) (5.4)
= 1004 – 554
ÃŽâ€TRS = 450
The weight combined feed ratio is calculated as;
(Flow rate)CLO * (Density)CLO * 2.204
CFR = (5.5)
(Flow rate)Fresh feed * (density)fresh feed * 2.204
=
CFR = 0.074
The stripping steam and inert gases carried to the reactor by the regenerated catalyst are calculated on a weight per pound fresh feed basis;
Steam = (5.6)
Steam = 0.01
Inert gases = (5.7)
Inert gases = 0.007
The amount of hydrogen in the coke is calculated as;
Hydrogen in Coke, wt % = [2.016 * 7.36 / 202.01] * 100 %
= 7.35 wt. %
The air to coke ratio is;
Air to coke, wt/wt = (2897/202.01) * (81.83/79)
Air to coke, wt/wt = 14.85 lbs air / lb coke
Where;
2897 is the molecular weight of air multiplied by 100 (basis of 100 moles of flue gas)
The weight of coke per hour may be calculated as;
Weight of coke, lbs/hr. = (4591) * 193.23 / 14.85
= 59738.6 lbs/hr.
Where;
(310717 Nm3/hr. = 5178.62 Nm3/min. = 193.23 MSCFM
4591 = air rate conversion factor from MSCFM to lbs/hr.)
So, weight % of coke is then;
wt. % coke = * 100%
= (59738.6 / 1104941.7) * 100 %
wt. % coke = 5.41
In the product yield table, the coke wt. % is indicted as 5.01 wt%. But it is calculated as 5.41 wt. %. Now the overall weight balance is as follows;
OVERALL WEIGHT BALANCE
INPUT:-
= Fresh feed + Coker naphtha + CLO recycle
= {(533.4 * 0.8 * 894 * 2.204) + (533.4 * 0.2 * 932 * 2.204)} + (30.2 * 676.2 * 2.204) + (46 * 808 * 2.204)
= 1186860.1 lbs. / hr.
OUTPUT:-
= Total product yields + coke
= 1149831 + 59738.6
= 1209569.6 lbs. / hr.
So, error in weight balance is calculated as;
= INPUT – OUTPUT
= (1186860.1 – 1209596.6) lbs. / hr.
= – 22736.5 lbs. / hr.
= – 1.88 wt. %
= 98.12 % closure
Now combustion heat of coke is determined as follows; (at hottest temperature = flue gas temperature = 1215oF)
ÃŽâ€Hcomb = [(X) (vol. % of CO in flue gas) + (Y) (vol. % of CO2 in flue gas) + (Z) (vol. % of O2 consumed)] / (weight if hydrogen and carbon in coke) (5.8)
= [(48000) * (0.005) + (169743) * (15.58) + (106472) * (7.36)] / 202.01
ÃŽâ€Hcomb = 16971.8 Btu / lb coke
Where;
X = heat of combustion of CO at 1215oF
Y = heat of combustion of CO2 at 1215oF
Z = heat of combustion of H2O at 1215oF
There is correction factor for the hydrogen in coke, this is given as;
Correction factor, C = 1133 – (134.6) (wt. % hydrogen) (5.9)
= 1133 – (134.6) (7.35)
= 143.7
The net heat of combustion after using the correction factor is;
-ÃŽâ€HC = 16971.8 + 143.7 Btu / lb coke
-ÃŽâ€HC = 17115.5 Btu / lb coke
At this point the reactor and regenerator heat balances are calculated. The catalyst supplies the heat to the reactor. The regenerator heat balance is calculated first using a basis of one pound of coke at the hottest regenerator temperature. The reactor heat balance is based on one pound of fresh feed.
HEAT BALANCE
REGENERATOR HEAT
(Figure: 2- Regenerator heat In – Out scheme)
HEATREG = ÃŽâ€HCOMB. – ÃŽâ€HCOKE – ÃŽâ€HAIR – ÃŽâ€HRADIATION LOSS (6.1)
Now, ÃŽâ€HCOKE = heat required to raise coke to combustion temperature
= (0.4) * (ÃŽâ€TRR) (6.2)
ÃŽâ€HAIR = heat required to raise air to combustion temperature
= (lb air / lb coke) * (0.26) * (ÃŽâ€TRB) (6.3)
ÃŽâ€HRADIATION LOSS = 250 Btu / lb coke
So, HEATREG = 17115.5 – {(0.4) * (180)} – {(14.85) * (0.26) * (776)} – 250
HEATREGHEATREG = 13797.4 Btu / lb coke
-ÃŽâ€HCSo, regenerator efficiency = *100% (6.4)
= 80.6
REACTOR HEAT
(Figure: 3- Reactor heat In – Out scheme)
HEATRX = ÃŽâ€HFRESH FEED + ÃŽâ€HRECYCLE + ÃŽâ€HSTRIPPING STEAM + ÃŽâ€HREACTION + ÃŽâ€HRADIATION LOSS + ÃŽâ€HINERTS (6.5)
ÃŽâ€HFRESH FEED, ÃŽâ€HRECYCLE = heat required to raise fresh feed & recycle to reactor temperature
ÃŽâ€HSTRIPPING STEAM = heat required to raise steam to reactor temperature
= ÃŽâ€TRS * (0.485) * (lb steam / lb fresh feed) (6.6)
ÃŽâ€HRADIATION LOSS = 2 Btu / lb fresh feed
ÃŽâ€HINERTS = heat of inert gases carried from regenerator to reactor by regenerated catalyst
= ÃŽâ€TRR * (-0.275) * (lb inerts / lb fresh feed) (6.7)
HEATRX = (enthalpy of fresh feed at riser outlet temperature – enthalpy of fresh feed at preheat temperature) + CFR (enthalpy of recycle feed at riser outlet temperature – enthalpy of recycle feed) + ÃŽâ€TRS * (0.485) * (lb steam / lb fresh feed) + 2 Btu / lb fresh feed + ÃŽâ€TRR * (-0.275) * (lb inerts / lb fresh feed) + ÃŽâ€HREACTION
= (745 – 460) + 0.074 * (745 – 460) + 450 * (0.485) * 0.01 + 2 + 180 * (-0.275) * 0.007 + ÃŽâ€HREACTION
HEATRX = 310 + ÃŽâ€HREACTION
Note:-
Enthalpies for the fresh feed and the recycle feed were calculated by taking respective UOP K values, oAPIs and the temperatures from the API technical data book.
Regenerator heat is calculated on a one lb of coke basis. This can be converted to one lb of fresh feed by use of weight % of coke term.
So, HEATRX = HEATREG () (6.8)
ÃŽâ€HREACTION + HEATRX = HEATREG () + ÃŽâ€HREACTION (6.9)
ÃŽâ€HREACTION = HEATREG () + ÃŽâ€HREACTION + HEATRX (6.10)
But HEATRX = + ÃŽâ€HREACTION
Putting this relation in equation (6.10), the equation changes to
ÃŽâ€HREACTION = HEATREG () –
ÃŽâ€HREACTION = 13797.4 * – 310
ÃŽâ€HREACTION = 436.44 Btu / lb fresh feed
So, HEATRX = 310 + 436.44
HEATRX = 746.44 Btu / lb fresh feed
(0.275) (ÃŽâ€TRR)Cat / Oil (wt. / wt.) = HEATRX (6.11)
Cat / Oil (wt. / wt.) = 15 lb Catalyst / lb Oil
Catalyst circulation rate = (Cat / Oil) * (lb fresh feed / hr.) (6.12)
= 15 * 1104941.8
CCR = 16574127 lbs. / hr.
= 7524 MT/ hr.
Overall heat flow scheme for the whole FCCU can be shown as below;
(Figure: 4- Typical FCCU heat balance scheme)
Now, the net total endothermic heat of reaction is calculated through empirical formulae. But we took the assumption as the riser is an isothermal one. Practically it is not isothermal. The temperature at the base of the riser is higher than what is at the top of the riser or at the riser outlet. This is because the cracking reactions occurring along the length of the riser is endothermic in nature. So heat is being absorbed during the reaction and causes the temperature at that particular location to decrease. Gradually the temperature decreases and at the riser outlet the temperature is dropped significantly. In this context we can estimate the riser base temperature using empirical relations and therefore can estimate the drop in temperature at the next differential element up in the riser [DNS]. But before this a multi-lumped model is to be considered along with possible reaction schemes and there kinetic parameters.
SEVEN LUMP KINETIC MODEL
For this purpose a seven lump kinetic model proposed by Mehran Heydari et al. (2010) is used. They divided the model into seven lumps namely; VGO/Coker Naphtha, Clarified Oil, Light Cycle Oil, gasoline (LCN, MCN, and HCN), LPG, Dry gas and Coke. The schematic flow diagram is as follows;
(Figure: 5- Seven lump kinetic model in FCCU)
In order to develop a mathematical model for this particular system, certain assumptions has to be taken, they are as follows;
The riser is an one dimensional ideal plug flow reactor with no radial and axial dispersion
Reactor is an adiabatic riser
Feed viscosity and heat capacities of all components are constant
Fluid flow is not affected by the coke deposition on the catalyst
Feed is vaporized instantaneously in the riser entrance
All cracking reactions are taking place in the riser
The model considers seven lumps and eighteen reactions and eighteen kinetic constants. Molecular weights of different lumps and boiling ranges are given [DNS] in the table below;
(Table: 5- molecular weights and boiling ranges of lumps)
j
Lump
Molecular weight
(Kg/ Kmol)
Boiling range
(oC)
1
VGO
418.7
349 – 620
2
CLO
291
232 -567
3
LCO
226
170 – 392
4
GASOLINE
114
30 – 228
5
LPG
65
–
6
DRY GAS
30
–
7
COKE
12
–
Values of kinetic constants and activation energies along with heat of reactions for each reaction are given in the table below ([DNS], [Mehran Heydari], [Praveen ch. & shishir sinha]);
(Table: 6- reaction schemes with kinetic parameters)
Reactions
Rate constants
(m3/ kg cat. hr.)
Activation energy
(KJ/Kmol)
Heat of reaction
(KJ/Kg)
VGO CLO
14.93
50.73
45.821
VGO LCO
5.78
50.73
79.213
VGO GASOLINE
11.69
50.73
92.335
VGO LPG
3.59
16.15
159.315
VGO DRYGAS
0.35
16.15
159.315
VGO COKE
11.55
16.15
159.315
CLO LCO
5.78
50.73
56.314
CLO GASOLINE
0.94
46.24
128.571
CLO LPG
0.135
59.75
455.185
CLO DRYGAS
0.0135
59.75
455.185
CLO COKE
0.3272
59.75
455.185
LCO GASOLINE
0.5742
46.24
93.030
LCO LPG
0.0086
59.75
704.93
LCO DRYGAS
0.0009
59.75
704.93
LCO COKE
0.0596
59.75
704.93
GASOLINE LPG
0.0003
78.49
372.10
GASO DRYGAS
0.0001
78.49
372.10
LPG DRYGAS
0.0033
59.75
32.30
The riser model is assumed to be a two phase model. The other assumptions are as follows [DNS];
Reaction mass consists of two phases, gas and solid
Riser is adiabatic
Catalyst activity can be correlated with coke on catalyst
Based on the assumptions, the reaction kinetics, material balance, heat balance in terms of jth lump in ith compartment are written while accounting for gas phase properties and catalyst activity.
REACTION KINETICS
Using the reaction schemes shown in figure: 5, the net rate of production of jth lump (kg/m3 s) in the ith compartment can be written as
Rj,i = Φi ÃÂgi (7.1)
Where j = 1, ….6 and q = 1, …….18
And the stoichiometric coefficients, α, is given in Table: 7 in the next page.
(Table: 7- Stoichiometric Co-efficient Matrix)[DNS]
Then the whole riser is divided into number of small compartments. For each compartment material and heat balance equations are written. The material balance equation for this model for a single compartment is as follows[to be written];
Then for each compartment the temperature is taken as constant and calculation is done to find out the outlet temperature from the particular compartment. The equations used for the calculations are as follows;
WCps (Teqi – Teqi-1) + FCpgi (Teqi – Teqi-1) = Hri (7.2)
Teqi = Teqi-1 + (7.3)
Hri = Vpi Φi ÃÂgi (7.4)
= Kq, i Yc j, i (7.5)
Tbase = [WCps (Trgn – 10) + FCplTl,in – Fλ – Qloss, riser] (7.6)
WCps + FCpv
To start with the iteration procedure, the riser base temperature has to be calculated and to be used in the above equation (7.3) as Teqi-1. Now, Tbase is calculated as follows;
Tbase = [2090 * 1.10 * (913 – 10) + (150 * 3.56 * 623) – (150 * 192) – 2]
[(2090 * 1.10) + (150 * 3.5)]
Tbase = 842 K
During its journey from the regenerator to the reactor, there is at least a 10o drop in temperature of regenerated catalyst in the transfer line. Qloss, riser is an empirical value, which is used to match the plant data for the riser base temperature. Now an iterative procedure is carried out using equation (7.3) in order to find the decrease in temperature in each compartment. Only 30 iterations are carried out, as at the end of the 30th iteration the value for the outlet temperature of the compartment was estimated to be 799.2 K (526.2oC), which is below the actual plant riser outlet temperature (540oC). The iterations are shown in a separate excel spread sheet. The reaction rates are known but the extent of conversions of products from reactants and also the extents of conversions of primary products to secondary products is not known precisely. So approximate values for the conversions are taken and based on that the conversions at each compartment is estimated and used further in other compartments to estimate approximately the drop in temperature due to endothermic cracking reactions inside the riser reactor. The iteration results are attached at the end of the report. Meanwhile apart from the losses that are accounted already in the calculation, some energy can always be recovered with different equipment arrangements. Those few cases are elaborated in the next chapter as energy saving ways in FCCU.
ENERGY SAVING WAYS IN FCCU
The FCCU is almost a self-sustaining unit in regards of energy. But excessive energy and losses are always associated with a process unit. So, finding out the possible and beneficial ways to recover the energy are of primary concern. Hence, few cases are discussed hereafter regarding energy conservation and utilization.
CASE – I – FCCU WITH POWER RECOVERY SYSTEM
Outline:
The flue gas containing CO at a higher content, generated from regenerator of FCCU is normally sent to CO boiler after reducing pressure by using a pressure reducing valve and pressure reducing orifice. Another arrangement can be done so as to recover a portion of the pressure energy of the flue gas in the form of power by installing an expansion turbine for pressure reduction. The flue gas after pressure reduction is sent to the CO boiler for combustion.
(Figure: 6- FCCU with gas expander turbine as power recovery system)
The gas expander turbine is attached with the air blower and a steam turbine on the same axis. 12-14 kg air per kg of coke is required normally for the combustion. Power required for injecting the air needs around 60 % of the total power requirement of the FCCU. So, installing the flue gas expander turbine can compensate some power and at the same time the load on the steam turbine can be reduced.
CASE – II – FCCU WITH REDUCED PRESSURE INSIDE REGENERATOR
Outline:
The pressure inside the FCCU can be reduced by increasing the capacity of the condenser at the top of the FCC fractionator. So, the pressure inside the regenerator is reduced and thereby the steam consumption to drive the air blower is also reduced.
(Figure: 7- FCCU with reduced pressure inside the regenerator)
The air fin cooler capacity is increased and the air pressure is reduced inside the regenerator column. It directly reduces the air pressure of the blower. Reduction in blower air pressure confirms the reduction in air volume of the blower along with reduction in specific consumption of high pressure steam to drive the steam turbine.
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